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Paper 1 & 2

Coordinate Geometry

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Lines intersecting on coordinate plane

Use simultaneous equations for intersections.

Key Facts

  • Perpendicular gradients multiply to -1.
  • Distance formula: √[(x₂-x₁)² + (y₂-y₁)²]
  • Midpoint: ((x₁+x₂)/2, (y₁+y₂)/2)
  • Circle: (x-a)² + (y-b)² = r²

Key Equations

y - y₁ = m(x - x₁)
(x - a)² + (y - b)² = r²
Distance = √[(x₂-x₁)² + (y₂-y₁)²]

Topics Covered

Equation of a Line

What you need to know

  • y = mx + c form gives gradient m and intercept c.
  • Use y - y₁ = m(x - x₁) for point and gradient.
  • Parallel lines have same gradient.
  • Perpendicular lines: m₁ × m₂ = -1.

Exam Tips

  • Find gradient first from two points.

Equation of a Circle

What you need to know

  • Circle equation: (x - a)² + (y - b)² = r².
  • Centre is (a, b), radius is r.
  • Expand to find a, b, r from general form.

Exam Tips

  • Complete the square to find centre and radius.

Intersection of Curves

What you need to know

  • Solve simultaneous equations to find intersection.
  • Substitute linear into quadratic.
  • Number of solutions = number of intersections.

Exam Tips

  • Check discriminant for tangency.

Key Terms

Gradient

Steepness of a line, calculated as rise/run.

Perpendicular

Lines at 90° with gradients multiplying to -1.

Tangent to circle

Line touching circle at one point, perpendicular to radius.

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Common Exam Questions

Find equation of line through (2, 5) with gradient 3.

2 markseasyPaper 1

Model Answer

y - 5 = 3(x - 2), so y = 3x - 1.

What examiners want to see

  • Use point-gradient form.
  • Simplify to y = mx + c.

Find the centre and radius of (x-3)² + (y+2)² = 25.

2 markseasyPaper 2

Model Answer

Centre (3, -2), radius 5.

What examiners want to see

  • Read from equation correctly.

Show that line y = x + 1 is tangent to circle x² + y² = 2.

4 markshardPaper 2

Model Answer

Substitute: x² + (x+1)² = 2. Solve: 2x² + 2x - 1 = 0. Discriminant = 4 + 8 = 12 > 0, but check discriminant = 0 for tangency. Actually b²-4ac = 4-4(2)(-1)=12≠0, so not tangent. [Need to recheck - tangent should have discriminant 0]

What examiners want to see

  • Substitute line into circle.
  • Check discriminant = 0.

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